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VIDEO ANSWER: In this problem, the variable is normally distributed with mean, mu equals 64, and standard deviation sigma equals 2. Based on this information alone, we want to answer A through D below. This questio
In 2002 ,the average height of a woman aged 20-74 years was 64 inches with an increase of approximately 1 inch from 1960 (http://usgovinfo.about.com/od/healthcare). Suppose the height of a woman is normally distributed with a standard deviation of two inches. (a) What is the probability that a randomly selected woman in this population is between 58 inches and 70 inches? (b) What are the quartiles of this distribution? (c) Determine the height that is symmetric about the mean that includes 90 % of this population. (d) What is the probability that five women selected at random from this population all exceed 68 inches? | Numerade